No, .9999… is not a limit, it’s a notation like using the infinity symbol. It is undisputedly equal to 1. Though you could represent it as a limit, that limit would also be the value of 1.
.1111… Uses the same concept to express a real number and isn’t a limit.
well 0.9999… is actually 1 because
This is muuuch better demonstrated by
1/3 = .33… 2/3 = .66… 3/3 = 0.99…
“Repeating” matters in approximations
Yes, but 0.99999999999999999999 isn’t 0.999… and therefore not 1, so it’s still wrong.
The software is wrong yes. I just had to share this information.
your 4th line reads as 10x^2 - x^2 = 9
You know I didn’t mean it like that, but you are technically right.
First thing that came to mind was this video by SingingBanana.
Great maths channel and he is a frequently on numberphile as well.
0.999… is lim(1), not 1.
No, .9999… is not a limit, it’s a notation like using the infinity symbol. It is undisputedly equal to 1. Though you could represent it as a limit, that limit would also be the value of 1.
.1111… Uses the same concept to express a real number and isn’t a limit.
What?
1 is a constant so lim(1) = 1